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Rewrite in vertex form: y=x^2+14x+50 Please help me understand.
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hi, still need a hand?
to get the eqution into vertex form, we will need to 'complete the square' do you know how to do this?
No sir I do not lol, I'm just really messed up on this.
no problem, we can get you all set up. here is what we are going to do, we need to 'rewrite' this: y=x^2+14x+50 which has a 'form' of y=Ax^2+Bx+c and we need to turn it into a 'form' of y=a(x-h)^2 + k do these 'forms' look familiar?
Yes they do, I seen that method before
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ok then to rewrite the equation into the 'vertex form' we will 'complete the square'
we take the coefficient that is infront of the 'x' term, and divide it by 2 |dw:1383856906155:dw|
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