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What is the solution to 3x^2+3x+5=0 (WILL GIVE MEDAL)
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Use the quadratic formula.
I know how to do that i just dont know what to do after i put the numbers in
\[x = \frac{ -b \pm \sqrt {b^2 - 4ac} }{ 2a }\] a = 3 , b = 3 , c = 5
just plug them in and simplify.
I'll get you started. \[x = \frac{ -3\pm \sqrt {3^2 - 4(3)(5)} }{ 2(3) }\]
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-3 +- sqrt(3^2 -4 (3)(5) -------------------- 2(3) ?? is that right?
Yeah
ok, im not sure how to simplify tho
Simplifying. We get. \[x = \frac{ -3 \pm \sqrt{9-60} }{ 6 }\] \[x = \frac{ -3 \pm \sqrt{-51} }{ 6 }\] \[x = \frac{ -1 \pm \sqrt{-51} }{ 2 }\]
ohh ok makes sense! Thank you so much!
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You're welcome.
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