Write the point slope form of the equation of the line passing through the point ( -12, -5) with a slope of 3.
@Directrix
The point-slope form of a linear equation looks like this: y - y1 = m*(x - x1) where m is the slope of the line and (x1,y1) is a point on the line.
@DeeBush96 Use that equation ^^^ to fill in for the slope and the point given in the problem. Post what you get and we will compare answers, okay?
i think it is y + 5+ 3(x+12) @Directrix
Yes, I almost agree. I think there's a typo here: y + 5+ 3(x+12) --> y + 5 = 3(x + 12)
so im rite
Yes, it you put an "equals" in your equation.
Find the values of x and y. The diagram is not a scale @Directrix
What is true about the two angles marked in red on the attachment? It has to do with parallel lines.
What name is given to those two angles marked in red? The name has to do with angles formed by two parallel lines cut by a transversal.
is it angle bisectors
No. They are alternate interior angles. Theorem: When two parallel lines are cut by a transversal, alternate interior angles are congruent.
ok
So, both have measure 40. Now, look at the diagram attached.
is X= 75 and Y=68
How did you get those?
Solve for y: 40 + y - 2 + 74 = 180 --> Sum of angles in triangle is 180
Simplify this: 40 + y - 2 + 74
can u help me simplify this
40 + y - 2 + 74 = 40 - 2 + 74 + y = ? Does that help?
40 - 2 + 74 = ?
112
@Directrix
Okay, so 40 + y - 2 + 74 = 180 112 + y = 180 y = ?
so do i subtract 112 from 180 @Directrix
Yes y = 180 - 112 y = ?
68 what is 8
y = 68
i meant what is x
Here is how to find x.
Solve for x: x -1 + 40 + 66 = 180
is it 75
Guessing from the options? :)
Yes, 75 = x.
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