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Mathematics 7 Online
OpenStudy (anonymous):

Which one of the following equations could describe the attached graph? A. y=2^(x+6) B. y=1.5^(x+2) -3 C. y=1/2^x +6 D. y=3^(x-1)

OpenStudy (anonymous):

OpenStudy (anonymous):

These are the answer choices written in proper form!

OpenStudy (anonymous):

the easiest way to know is just use x = 0 that would give you a point then check if that point is in the graph

OpenStudy (anonymous):

@JAMG so even in A it would be y=2^(0+6) ?? I'm kind of confused :(

OpenStudy (anonymous):

Simple way: If you take a point on the graph, (1, 1) or (2, 3), notice that when x =1, y =1 Using that, plug this into each of the formulas, x=2, y=3 is another choice which gives the answer. (Pick easy points to read from the graph, if they exist) Conceptually: x-r is a transformation that shifts functions to the right by 'r' For example, 3^(x-1) is the graph of 3^x, shifted one unit to the right.

OpenStudy (anonymous):

when x = 0 A y = 2^6 which is clealry a big number B y = 1.5^2 - 3 which is a negative number C y = 1/2^2 + 6 which is 7 D y = 3^-1=1/3 => (0 , 1/3)

OpenStudy (anonymous):

oh so it would be D since that point is right on the graph?! :o

OpenStudy (anonymous):

yep :D

OpenStudy (anonymous):

thank you SO much & for explaining why it wasn't the other answers!! :)

OpenStudy (anonymous):

if all have that point use x = 1 which is another easy number to compute :D

OpenStudy (anonymous):

thank you very much :)

OpenStudy (anonymous):

np :D

OpenStudy (anonymous):

Refer to the attachment from Mathematica 8 Home Edition.

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