Solve by completing the square: -x^2+6x+10=0

Last one lol, please help.

Question

Solve by completing the square: -x^2+6x+10=0

Last one lol, please help.

anonymous · Answer

Help?lol, I know I have to add to both sides. I just need help lol.

radar · Answer

Multiply thru by -1 getting x^2 -6x-10=0. Look closely at the x^2 -6x  what would be here x^2 -6x ________ to be a perfect square?
How about x^2 -6x + 9 ???? that would be the same as (x-3)^2.  To get a +9 I must add 19 which I will do:x^2 - 6x +9 = 19  After adding 19 to both sides.  Follow so far??

radar · Answer

-10+19 = 9.

Now we write it like this (x -3)^2 = 19   
Take the square root of both sides getting
$$x-3 = \sqrt{19}$$$$x = 3 \pm \sqrt{19}$$

radar · Answer

I hope you could follow that @ILoveLove

anonymous · Answer

Yes sir I do, for the final answer would be to the second equation you have?

radar · Answer

The final answer is$$x =3\pm \sqrt{19}$$Which would be spoken as 3 plus and minus the square root of 19