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Mathematics 10 Online
OpenStudy (anonymous):

Please help!

OpenStudy (anonymous):

A catapult launches a boulder with an upwark velocity of 184 feet per second. The height of the boulder in feet after t seconds is given by the function h(t)=-16t^2+184t+20. How long does it take the boulder to reach its maximum height? What is the boulders maximum height? Round to the nearest hundredth, if necessary. a.Reaches maximum height of 11.6 feet after 5.75 seconds b. Reaches maximum height of 549 feet after 11.5 seconds. c.Reaches a maximum height of 549 feet aftter 5.75 seconds d. Reaches a maximum height of 23.2 feet after 11.6 seconds.

OpenStudy (anonymous):

you have to put it in the form y=a(x-h)^2 + k by factoring h(t)= -16t^2 + 184t +20 when you do that, the k value will be your maximum height

OpenStudy (anonymous):

and h will be the time of its maximum height

OpenStudy (anonymous):

do you get it?

OpenStudy (anonymous):

not really...

OpenStudy (anonymous):

did you factor it?

OpenStudy (anonymous):

i dont know how

OpenStudy (anonymous):

how about i show you an example?

OpenStudy (anonymous):

yes please

OpenStudy (anonymous):

OpenStudy (anonymous):

Hope that helps ^_^

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