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The function f(x)= -a^x +4 will never cross the x-axis. True or false??
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I think its true
um i agree with @NaomiBell1997
I think it is true, also, it will approach it closely, but never cross
can someone help me with my question
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I think I just did.
ali1029 do you know how \(\bf y= x^2\) looks like?
If a > 1, the function can cross the x axis. y = -a^x +4 To find where it crosses or touches the x axis, set y = 0 and solve for x 0 = -a^x + 4 add a^x to both sides a^x = 4 take log on both sides xlog(a) = log(4) x = log(4) / log(a) is the point where it will cut/touch the x axis for a > 1
if a was positive, would the answer be false?
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