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Solve by variation of parameters. I'm so close on this... I just got to put it in the correct format. y''+y=cscx
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answer is y=(c1-x)cosx+(c2+ln(sinx))sinx I got these terms in separate areas...do I combine them?
like that? since if yh = c1cosx+c2sinx and yp = -xcosx+ln(sinx)sinx? then yh+yp
and factor
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@phi
yes, the complete solution is y = yp + yh
which you can write as you posted: y=(c1-x)cosx+(c2+ln(sinx))sinx
whoa for a second I thought you were just a trolling account stalking my page, but it seems that you know a lot of stuff
I'm currently doing another one of these problems. wanna help? like I'm getting there...just doing integration
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k :(
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