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Mathematics 13 Online
OpenStudy (usukidoll):

Solve by variation of parameters. I'm so close on this... I just got to put it in the correct format. y''+y=cscx

OpenStudy (usukidoll):

OpenStudy (usukidoll):

answer is y=(c1-x)cosx+(c2+ln(sinx))sinx I got these terms in separate areas...do I combine them?

OpenStudy (usukidoll):

OpenStudy (usukidoll):

like that? since if yh = c1cosx+c2sinx and yp = -xcosx+ln(sinx)sinx? then yh+yp

OpenStudy (usukidoll):

and factor

OpenStudy (usukidoll):

@phi

OpenStudy (phi):

yes, the complete solution is y = yp + yh

OpenStudy (phi):

which you can write as you posted: y=(c1-x)cosx+(c2+ln(sinx))sinx

OpenStudy (usukidoll):

whoa for a second I thought you were just a trolling account stalking my page, but it seems that you know a lot of stuff

OpenStudy (usukidoll):

I'm currently doing another one of these problems. wanna help? like I'm getting there...just doing integration

OpenStudy (usukidoll):

k :(

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