Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (anonymous):

A sample set contains the following data: {2.5, 4.1, 6, 8, 9, 9, 9.5, 10}. Approximately where is the mean value located? A. Closer to 2.5 than 10 B. Closer to 10 than 2.5 C. Halfway between 2.5 and 10 D. It has more than one location. I got A!

OpenStudy (anonymous):

SORRY ITS b

OpenStudy (anonymous):

i got 7.2635 and thats much closer to 10

OpenStudy (agent0smith):

Looks about right. Just add them all up and divide by how many there is.

OpenStudy (agent0smith):

"6, 8, 9, 9, 9.5, 10}." but all these numbers are closer to 10 than 2.5 so you can estimate it's near 10

Directrix (directrix):

I used this online calculator at http://easycalculation.com/statistics/mean-median-mode.php It popped out 7.2625.

OpenStudy (agent0smith):

2.5, 4.1 are the only two below 5, the rest are all above 5

Directrix (directrix):

Then, I did the mean of these: Halfway between 2.5 and 10. That did not bear fruit. >>> good thinking here: 2.5, 4.1 are the only two below 5, the rest are all above 5

OpenStudy (agent0smith):

Halfway between 2.5 and 10 that would be 6.25 exactly so i'm guessing we can ignore that one

OpenStudy (agent0smith):

Oh i didn't notice you'd already done that, directrix

Directrix (directrix):

So, that leaves option B, I suppose.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Arriyanalol: i need help
17 hours ago 7 Replies 1 Medal
Arriyanalol: CONGRATS to me
20 hours ago 8 Replies 2 Medals
Legomaster346: What colleges are good that are near Arab Alabama?
1 week ago 5 Replies 0 Medals
Arriyanalol: i need help
1 week ago 6 Replies 2 Medals
Arizona: does anyone know the percentage rate of 30,000 and 40,000
1 week ago 0 Replies 0 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!