16=(1/4)^-2
Is that a true or false?
I need to write this equation in logarithmic form
True!
Ok, so log is simple to convert when written that way. The base that have our exponent is our log base. \[\log_{1/4} \]
-2 is the exponent so would that b the log?
Next, we see what that the equation equals and say that \[\log_{1/4}(10) \] This is pronounced as log base of 1/4 of 10.
*16
\(\bf 16=\left(\cfrac{1}{4}\right)^{-2}\qquad \qquad log_ab=c\implies a^c=b\qquad thus\\ \quad \\ \large log_{\frac{1}{4}}(16)=-2\)
okay i see it now ty
Finally we see what our exponent is and write that on the other side of the = sign. \[\log_{1/4}(16)=-2 \]. Think about it this way (1/4)^-2=16. |dw:1384045223511:dw| And that's how you caonvert between logs and exponentials.
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