For the function f(x) = x + 7, what is the ordered pair for the point on the graph when x = 2b
A. ( 2b, 2b+7)
B. ( 2b, x + 7)
C.( x, x + 7 )
D. (x, 2b + 7)
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OpenStudy (ajprincess):
in the ordered pair the first value will be the value of x and the second value will be the value of f(x). u can get the value of f(x) by plugging the given value of x in f(x). Does that help?
OpenStudy (anonymous):
Kinda but how do you get the value of x
OpenStudy (ajprincess):
It is given
OpenStudy (anonymous):
so the answer is b.
OpenStudy (ajprincess):
nope. find the value of f(x) when x=2b
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OpenStudy (math&ing001):
The pair looks like this (x;y) with y=f(x). Gues again
OpenStudy (math&ing001):
guess*
OpenStudy (anonymous):
i am confused but is it answer d then
OpenStudy (ajprincess):
nope
OpenStudy (ajprincess):
what is the value of x given>
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OpenStudy (math&ing001):
You replace x with 2b
OpenStudy (math&ing001):
You replace x with 2b on everything. There shouldn't be any x left in your final answer.
OpenStudy (anonymous):
oh ok thanks
OpenStudy (anonymous):
can you help me with one more
OpenStudy (math&ing001):
Ok
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OpenStudy (math&ing001):
Btw what answer did you get for the first ?
OpenStudy (anonymous):
Find the f(5)
f(1) = 2 and f(2) = 4, f(1) + f (2) +f(n-1), for n > 2
so f(5) =
OpenStudy (anonymous):
i got for the first one A.
OpenStudy (math&ing001):
That's correct. Gz!
OpenStudy (math&ing001):
There's something wrong about this part f(1) + f (2) +f(n-1)
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OpenStudy (anonymous):
oh yeah before the f(1) there should have been a f(n)= so like 4,f(n) = f(1)
OpenStudy (math&ing001):
You should find f(3) and f(4) before you can find f(5).
You just replace n with 3 on this f(n) = f(1) + f (2) +f(n-1) and replace f(1) and f(2) with their respectives values.
Same for f(4).
OpenStudy (anonymous):
D.
OpenStudy (anonymous):
for the first one
OpenStudy (anonymous):
well actually its A but thanks for answering
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OpenStudy (anonymous):
oh
OpenStudy (anonymous):
i knew that
OpenStudy (anonymous):
Then why did you say D.
OpenStudy (anonymous):
by accident
OpenStudy (anonymous):
not kidding
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