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Mathematics 20 Online
OpenStudy (yacoub1993):

Multiply or divide as indicated.

OpenStudy (yacoub1993):

\[\frac{ 2x }{4x+2} \times \frac{ 14x+7 }{ 6 }\]

hartnn (hartnn):

factor out 7 from 14x+7 can you ?

OpenStudy (yacoub1993):

no can u show ,me

hartnn (hartnn):

14x+7 = 7*2*x+7 the '7' there is common to both terms, so i factor it out to get 7 (2x+1) got this ?

OpenStudy (yacoub1993):

Yes what u said, i got then continue please

hartnn (hartnn):

similarly, factor out 2 from 4x+2 can you ?

OpenStudy (yacoub1993):

2x+1

hartnn (hartnn):

4x+2 = 2 (2x+1) isn't it ?

OpenStudy (yacoub1993):

YES

hartnn (hartnn):

so, \(\large \frac{ 2x }{4x+2} \times \frac{ 14x+7 }{ 6 }= \frac{ 2x }{2(2x+1)} \times \frac{ 7(2x+1) }{ 6 }\) what gets cancelled out ?

OpenStudy (yacoub1993):

WAit

OpenStudy (yacoub1993):

continue

hartnn (hartnn):

anything getting cancelled from numerator and denominator ?

hartnn (hartnn):

\(\large \large \frac{ 2x }{4x+2} \times \frac{ 14x+7 }{ 6 }= \frac{ \cancel 2x }{\cancel 2\cancel{(2x+1)}} \times \frac{ 7\cancel{(2x+1)} }{ 6 }\) got this ?

OpenStudy (yacoub1993):

yes i got so we multiply x with 7/6

hartnn (hartnn):

correct! so final answer = 7x/6 :)

OpenStudy (yacoub1993):

is the answer 7x/6 or 7/6 only

OpenStudy (yacoub1993):

ohhh thnxs

hartnn (hartnn):

welcome ^_^

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