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OpenStudy (yacoub1993):
Multiply or divide as indicated.
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OpenStudy (yacoub1993):
\[\frac{ 2x }{4x+2} \times \frac{ 14x+7 }{ 6 }\]
hartnn (hartnn):
factor out 7 from 14x+7
can you ?
OpenStudy (yacoub1993):
no can u show ,me
hartnn (hartnn):
14x+7 = 7*2*x+7
the '7' there is common to both terms, so i factor it out to get
7 (2x+1)
got this ?
OpenStudy (yacoub1993):
Yes what u said, i got then continue please
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hartnn (hartnn):
similarly, factor out 2 from 4x+2
can you ?
OpenStudy (yacoub1993):
2x+1
hartnn (hartnn):
4x+2 = 2 (2x+1)
isn't it ?
OpenStudy (yacoub1993):
YES
hartnn (hartnn):
so,
\(\large \frac{ 2x }{4x+2} \times \frac{ 14x+7 }{ 6 }= \frac{ 2x }{2(2x+1)} \times \frac{ 7(2x+1) }{ 6 }\)
what gets cancelled out ?
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OpenStudy (yacoub1993):
WAit
OpenStudy (yacoub1993):
continue
hartnn (hartnn):
anything getting cancelled from numerator and denominator ?
hartnn (hartnn):
\(\large \large \frac{ 2x }{4x+2} \times \frac{ 14x+7 }{ 6 }= \frac{ \cancel 2x }{\cancel 2\cancel{(2x+1)}} \times \frac{ 7\cancel{(2x+1)} }{ 6 }\)
got this ?
OpenStudy (yacoub1993):
yes i got so we multiply x with 7/6
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hartnn (hartnn):
correct!
so final answer = 7x/6 :)
OpenStudy (yacoub1993):
is the answer 7x/6 or 7/6 only
OpenStudy (yacoub1993):
ohhh thnxs
hartnn (hartnn):
welcome ^_^
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