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Inequalities help? 1. x – 3 > –9 2. –2x + 1 ≤ –11 3. 10 < –3x + 1 4. 2(x + 5) > 8x – 8 5. –2(x – 3) ≥ 5 – (x + 3)
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1. you have to add 3 to both sides to get x alone. and -9+3 is -6 so it's x>-6
Okay, so for number two, If I subtracted one from both sides, it would be -2x < -12?
I'm trying to apply the same terms.
Thank you, this is what I needed.
2. You have to subtract 1 from the -11. So you'd get -2x≥-12 (since you are now dividing by a negative my teacher told us to switch the sign around) You divide by -2 and get x≥6
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