2x2 + 12x = 10 −3 ± square root 14 −3 ± 2square root 2 −3 ± square root 19 −3 ± square root 29
So I take it we must use the quadratic formula here..
honestly I have no idea lol im lost as crap with this
\[2x ^{2}+12x-10=0\]
\[\frac{ -b \pm \sqrt{b ^{2}-4ac} }{ 2a }\]
A = 2 B = 12 C = -10 Do you understand... how I chose those numbers first?
not a clue man, I don't understand any of this stuff
\[ax ^{2}+bx+c = 2x ^{2}+12x-10\]
Now you see why 2 is a and 12 is b and -10 is c?
uhhh..sure
how do you find the answer
The formula... I am simply going to plug these numbers into their respective spots.
So it is imperative that you understand where I am pulling these numbers from... here we go...
\[\frac{ -12\pm \sqrt{12^{2}-4(2)(-10)} }{ 2(2) }\]
So now, if we simplify this... we should get...
\[\frac{ -12\pm \sqrt{224} }{ 4 }\]
\[\frac{ -3\pm 4\sqrt{14} }{ 4 }\]
The 4's reduce...
−3 ± square root 14 is your answer @tiffanyr96
Hopefully that helps somewhat... I understand that Math is everyone's cup of tea.
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