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Mathematics 9 Online
OpenStudy (anonymous):

SUMMATION NOTATION:Getting so annoyed! I was so sure this was the answer. I have tried this problem 3 times, and have 2 attempts left. I was so sure this time :C (comments)

OpenStudy (anonymous):

OpenStudy (anonymous):

Do you have to do this by hand?

OpenStudy (anonymous):

I believe it is 20.

hartnn (hartnn):

how did you get 23 ? maybe can help you find the error

OpenStudy (anonymous):

I did it by hand to be extra sure!

OpenStudy (anonymous):

Hartnn, I hand calculated each of the terms up to twenty, then added them. Gave me 23.

hartnn (hartnn):

so, 2 (-1+ 2-3+4-5+6.....+20) this right ?

hartnn (hartnn):

lets take 2 terms at a time \(2 ( [-1+2]+ [-3+4]+ ... [-19+20])\) what does each pair equal to ?

OpenStudy (anonymous):

I complicated myself by doing a1, a2,a3...uo until 20 then plugging the numbers in the formula xD

hartnn (hartnn):

thats one way, but do you get what i am doing ?

hartnn (hartnn):

not +1 ?

OpenStudy (anonymous):

So far, yeah.

hartnn (hartnn):

and how many such pairs are there ?

OpenStudy (anonymous):

FYI, I did what hartnn did so if he gets the same answer go with him.

hartnn (hartnn):

10 pairs ?

OpenStudy (anonymous):

Sorry, my internet is laggy.

hartnn (hartnn):

no problem

OpenStudy (anonymous):

Yes, there would be ten in doing the pairs.

hartnn (hartnn):

good, so 1+1+1..1 (10 times)= 10 and 2 (10) = 20 thats your sum!

OpenStudy (anonymous):

Damn, all those numbers to figure out how not to do it T-T. Thank you again Hartnn!

OpenStudy (anonymous):

Would have been so much easier u__u

hartnn (hartnn):

lol welcome ^_^ do you also want to know how do we do it using formulas ?

OpenStudy (anonymous):

I would o_o

hartnn (hartnn):

ok, so we have \(2 [(2+4+6+...20)- (1+3+5+...19)]\) got this break up ? we will find the sum of these 2 series separately

hartnn (hartnn):

these both are arithmetic series do you know the formula for sum of arithmetic sequences ?

OpenStudy (anonymous):

I only know n = a1 + (n – 1)d

hartnn (hartnn):

thts n'th term formula what about sum formula ?

hartnn (hartnn):

this qestion belongs to arithmetic sequence topic, right ?

OpenStudy (anonymous):

sn = n(a1+a2) over 2? That is correcto mundo.

hartnn (hartnn):

its Sn = (n/2) (a1+ an) an is last term

OpenStudy (anonymous):

Oh T-T

hartnn (hartnn):

so for 1st sequence 2+4+...20 whats a1 = .. an =.. n= .. ?

OpenStudy (anonymous):

a1=2, an=20, n=10?

hartnn (hartnn):

correct! so find the sum

OpenStudy (anonymous):

I got Sn = 5+n o.o

hartnn (hartnn):

how ?

hartnn (hartnn):

and n= 10 as you said

OpenStudy (anonymous):

Never mind...should be 15, no?

hartnn (hartnn):

no

hartnn (hartnn):

Sn = (10/2) (2+20) = 5 *22 = ...

OpenStudy (anonymous):

Crap, I was using an=10...

OpenStudy (anonymous):

5*22=110

hartnn (hartnn):

yes so for 2nd sequence 1+3+...19 whats a1 = .. an =.. n= .. ?

OpenStudy (anonymous):

a1=1, an=19, n=9

hartnn (hartnn):

n= 10 right ?

OpenStudy (anonymous):

Wait, I know it isn't 9, but how 10?

hartnn (hartnn):

1 is 1st term, 19 is last term (19-1)/2 + 1 = 10

OpenStudy (anonymous):

Alright, sorry. Go on.

hartnn (hartnn):

so find the sum

OpenStudy (anonymous):

100

hartnn (hartnn):

correct!

hartnn (hartnn):

2 (110-100) = ...

hartnn (hartnn):

any doubts anywhere ?

OpenStudy (anonymous):

No, no doubts Mr Hartnn u__u Thank you very much for your precious time.

hartnn (hartnn):

you're most welcome ^_^

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