SUMMATION NOTATION:Getting so annoyed! I was so sure this was the answer. I have tried this problem 3 times, and have 2 attempts left. I was so sure this time :C (comments)
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OpenStudy (anonymous):
OpenStudy (anonymous):
Do you have to do this by hand?
OpenStudy (anonymous):
I believe it is 20.
hartnn (hartnn):
how did you get 23 ? maybe can help you find the error
OpenStudy (anonymous):
I did it by hand to be extra sure!
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OpenStudy (anonymous):
Hartnn, I hand calculated each of the terms up to twenty, then added them. Gave me 23.
hartnn (hartnn):
so,
2 (-1+ 2-3+4-5+6.....+20)
this right ?
hartnn (hartnn):
lets take 2 terms at a time
\(2 ( [-1+2]+ [-3+4]+ ... [-19+20])\)
what does each pair equal to ?
OpenStudy (anonymous):
I complicated myself by doing a1, a2,a3...uo until 20 then plugging the numbers in the formula xD
hartnn (hartnn):
thats one way,
but do you get what i am doing ?
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hartnn (hartnn):
not +1 ?
OpenStudy (anonymous):
So far, yeah.
hartnn (hartnn):
and how many such pairs are there ?
OpenStudy (anonymous):
FYI, I did what hartnn did so if he gets the same answer go with him.
hartnn (hartnn):
10 pairs ?
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OpenStudy (anonymous):
Sorry, my internet is laggy.
hartnn (hartnn):
no problem
OpenStudy (anonymous):
Yes, there would be ten in doing the pairs.
hartnn (hartnn):
good,
so 1+1+1..1 (10 times)= 10
and 2 (10) = 20
thats your sum!
OpenStudy (anonymous):
Damn, all those numbers to figure out how not to do it T-T. Thank you again Hartnn!
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OpenStudy (anonymous):
Would have been so much easier u__u
hartnn (hartnn):
lol welcome ^_^
do you also want to know how do we do it using formulas ?
OpenStudy (anonymous):
I would o_o
hartnn (hartnn):
ok, so we have
\(2 [(2+4+6+...20)- (1+3+5+...19)]\)
got this break up ?
we will find the sum of these 2 series separately
hartnn (hartnn):
these both are arithmetic series
do you know the formula for sum of arithmetic sequences ?
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OpenStudy (anonymous):
I only know n = a1 + (n – 1)d
hartnn (hartnn):
thts n'th term formula
what about sum formula ?
hartnn (hartnn):
this qestion belongs to arithmetic sequence topic, right ?
OpenStudy (anonymous):
sn = n(a1+a2) over 2? That is correcto mundo.
hartnn (hartnn):
its Sn = (n/2) (a1+ an)
an is last term
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OpenStudy (anonymous):
Oh T-T
hartnn (hartnn):
so for 1st sequence 2+4+...20
whats a1 = ..
an =..
n= ..
?
OpenStudy (anonymous):
a1=2, an=20, n=10?
hartnn (hartnn):
correct!
so find the sum
OpenStudy (anonymous):
I got Sn = 5+n o.o
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hartnn (hartnn):
how ?
hartnn (hartnn):
and n= 10 as you said
OpenStudy (anonymous):
Never mind...should be 15, no?
hartnn (hartnn):
no
hartnn (hartnn):
Sn = (10/2) (2+20)
= 5 *22 = ...
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OpenStudy (anonymous):
Crap, I was using an=10...
OpenStudy (anonymous):
5*22=110
hartnn (hartnn):
yes
so for 2nd sequence 1+3+...19
whats a1 = ..
an =..
n= ..
?
OpenStudy (anonymous):
a1=1, an=19, n=9
hartnn (hartnn):
n= 10
right ?
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OpenStudy (anonymous):
Wait, I know it isn't 9, but how 10?
hartnn (hartnn):
1 is 1st term, 19 is last term
(19-1)/2 + 1 = 10
OpenStudy (anonymous):
Alright, sorry. Go on.
hartnn (hartnn):
so find the sum
OpenStudy (anonymous):
100
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hartnn (hartnn):
correct!
hartnn (hartnn):
2 (110-100) = ...
hartnn (hartnn):
any doubts anywhere ?
OpenStudy (anonymous):
No, no doubts Mr Hartnn u__u Thank you very much for your precious time.