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notice that u have \[\large \frac{A}{D}+\frac{B}{D}-\frac{C}{D}=\frac{A+B-C}{D} \]
Right. But the middle term cannot be factored so it won't solve for me.
it doesn't matter. just do A+B-C first. then factor if possible
do \[\large (2x^2+8x+20)+(3x^2-15x-44)-(4x^2-7x-15) \] first
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So I came up with \[x^2-14x-39\] which cannot be factored further.
i got \[\large x^2-9 \]
which can be factored
Thanks got it figured out.
u r welcome
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