Question

solve the inequality
6(3x-1)<=8(2x-8)

Answer 1

\[6(3x-1)\le8(2x-8)\]

As you multiply, divide, and add. Remember that whatever you do, as long as you do the same thing to both sides you are ok
so to start distribute the 6 in 6(3x-1) and get
\[18x-6\le8(2x-8)\]

Answer 2

then distribute the 8 in 8(2x-8) and get
\[18x-6 \le 16x-64\]

Answer 3

subtract 16x from both sides and get
\[2x-6\le-64\]

Answer 4

then add 6 to both sides and get
\[2x \le -58\]

Answer 5

then divide by 2 and get
\[x \le -29\]
that's your final answer.

Answer 6

Thank you so much