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How do I find B so that f(x) is a continuous RV pdf?
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\[f(x) = \int\limits\limits_{-\infty}^{\infty}\frac{ 1 }{ \sqrt{\pi} } \exp(-x^2 + x - b)dx =\int\limits\limits_{-\infty}^{\infty}\frac{ 1 }{ \sqrt{\pi} } \exp[-(x-0.5)^{2} -b +0.25)] dx = 1\]
I simplified it so that it looks like a gaussian distribution and I also know that the integral from -infinity to infinity should be 1 if it's a continuous pdf
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