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In the game of “rock,” “scissors,” “paper,” if the player follows the rules and truly chooses at random, what is the probability of the opponent not selecting “scissors”? Hint: Use the complementary rule. A. 0 B. 1/3 C. 2/3 D. 1
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c
P(Scissors) = 1/3, right? Scissors and Not Scissors are mutuakky exclusive, right? P(Scissors) + PNot Scissors) =1, right?
mutually
mutually i think you meant lol
darn k wasn't where it was supposed to be!
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lol
2/3 because u have 2 chances out of the 3 of not picking scissors
thank you guys
np
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