Question

how do you solve x^4-4x^2+3=0

Answer 1

Factor: (x^2 - 1)(x^2 - 3) = 0

Answer 2

Now, set each factor equal to 0, and find all 4 values of x.

Answer 3

All four? Why wouldn't it be two?

Answer 4

x^2 - 1 = 0
(x-1)(x+1) = 0
x = 1, x = -1

x^2 - 3 = 0
x = sqrt(3) and -sqrt(3)

Thats why I made sure to mention "4 zeros", as it may be overlooked.

Answer 5

x^2 - 3 = 0
x^2 = 3
x = sqrt(3) and - sqrt(3)

Answer 6

Alright. That makes more sense. Thanks

Answer 7

welcome.

Answer 8

@Kate2997