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find the equation for the line that passes through the point (1,-3) and that is parallel to the line with the equation (y-2)=1/4 (x+4)
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parallel means same slope, so the slop is 1/4
next just plug the point (1,-3) into a point-slope equation format and ur done!
How would I be able to do that?
(y-2)=1/4 (x+4) its the same format as this
(y-y1)=m (x+x1) where m = the slop which is 1/4. (x1, y1) is the coordinate of ur point (1,-3)
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Is the answer y=1/4x+13/4?
u mean y=1/4x - 13/4?
y-(-3) = y+3
so you would subtract 3 from both sides
Okay that makes sense. Thank You.
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no problem
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