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What is the number of real solutions? –11x2 = x + 11 cannot be determined one solution two solutions no real solutions
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I think it is cannot be determined... but I want someone to check my answer.
rewrite: \[11x^2+x+11=0\] a = 11, b = 1, c = 11 \[b^2-4ac= 1-4(11)(11) <0 \Rightarrow \text{complex zeros}\]
So there are zero solutions?
no. have a look... http://www.mathwarehouse.com/quadratic/discriminant-in-quadratic-equation.php
There are two real solutions!
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nope
Negative Discriminant b² − 4ac < 0 No Real Solutions Two Imaginary Solutions
there you go!
So there are no real solutions?
yep
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