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q+12-2(q-22)>0
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where u stuck at?
the whole thing
k, so first distribute the 2 in this part, "2(q-22)" what do you get?
2q 20
2q-(2)*22 2q-44 now we have q + 12 + 2q - 44 > 0 combine like terms now
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3q ?
the 3q is right, but what about the rest of the equation? 3q + 12 - 44 >0
do i put a number on both sides ? or no like 12 under 12 and 14 under 12
mmm.... I think you are second guessing you self! ^_^ just do 12-44 = -32 so we now have 3q - 32 > 0 next, 'isolate' the q term by moving the -32 to the same side as the 0
thank you so much it was right .
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yep ^_^
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