Question

how would you factor 8r^6+27s^12

Answer 1

make use of the identity

a^3 + b^3 = (a + b)(a^2 - ab + b^2)

hold on- i'll check to see if i remember that one correctly)

Answer 2

yes thats right

so if you compare your expression with the above you get

a = 2r^2 ( because 8r^6 = (2r^2)^3
and b = 3s^4

so plug these in to the formula for a^3 + b^3 and you've got it