Question

is the line through the points R(-1,3) and S (2,-7) parallel to the graph of the line given by the equation 10x+3y=6

Answer 1

find the slope between R and S. if it is the same as the slope of the given line, then they r parallel

Answer 2

a.no, the slopes have opposite signs.b.yes, the slopes have the same sign and value. c.yes, the lines bith decrease to the right. d.no, the lines have unequal slopes

Answer 3

do u know how to compute the slope between two points?

Answer 4

no, sorry

Answer 5

ok given R(a,b) and S(c,d) then the slope is given by
\[\large m=\frac{b-d}{a-c} \]
try it.

Answer 6

sorry, I just wouldn't know how

Answer 7

ok u have R(-1,3) and S(2,-7) then the slope is
\[\large m=\frac{3-(-7)}{-1-2}=\frac{3+7}{-1-2}=\frac{10}{-3}=-\frac{10}{3} \]

Answer 8

got it?

Answer 9

I will keep studying this, thank you :)

Answer 10

so b then right?

Answer 11

the next step would be to get y in terms of x.
u have
\[\large 10x+3y=6 \]
from which
\[\large y=-\frac{10}{3}x+2 \]
and the slope of this line is -10/3

Answer 12

u r right, it is B

Answer 13

thank you :)

Answer 14

u r welcome