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Convert from radical to exponential form, is this correct?(wait till I finish writing the formulas please.)
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\[\sqrt[5]{32d ^{3}e ^{5}f} = 2^{\frac{ 1 }{5 }}d ^{\frac{ 3 }{ 5 }} f ^{\frac{ 1 }{ 5 }}\]
The variables are okay.. But 32 is 2^5....the 5th root of 2^5 is just 2...so you don't need an exponent on your 2 in the answer.
Think of it as (2^5)^1/5 which is 2^(5*1/5) which is 2^1 or 2
@BangkokGarrett Where is the e?
ooops you forgot the e. there should be an e in the answer.
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oops yeah I forgot the e
(e^5)^1/5 = e^(5*1/5) = e^1 = e
I'm confused
help
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