Question

Find x : e^x e^(x+1) = 1 will give medals!!

Answer 1

(e^x)(e^(x+1)) = e^(2x+1) [Law of Exponents]

So e^(2x+1) = 1

The trick is to write 1 as e^0.

so you have e^(2x+1) = e^0

so equate the exponents (since both bases are e)

therefore, 2x + 1 = 0
x = -1/2

@QueenBee232