Which set is closed under the operation multiplication?
A.
{1, 2, 3}
B.
{0, 1}
C.
{0, 1, 2}
D.
{1, 2}
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OpenStudy (anonymous):
A set is closed under multiplication if you take any two members of the set and multiply them, the product will be in the set. You can even take a member and multiply it by itself.
So, {2,4} is not closed under multiplication because 2 x 4 = 8, and 8 is not inside that set {2,4}.
OpenStudy (anonymous):
if I understood that correctly
then after looking at the answers provided
I don't see one that fit's
what you said
OpenStudy (anonymous):
@Easyaspi314 are you there?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
Oh no? what about choice B, {0,1}?
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OpenStudy (anonymous):
this is my last question and it's the most important
OpenStudy (anonymous):
0 x 0 = 0
0 x 1 = 0
1 x 1 = 1
0 x 0 = 0
OpenStudy (anonymous):
Post any new question you may have as a new post.
You're welcome.
OpenStudy (anonymous):
I thaught you said the number hase to be outside of the set...
and
thank you
OpenStudy (anonymous):
rad again what I said.
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