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Factor: 4x^(3x+1) - 32x^(5n+3)
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so we have: \[4x ^{(3x+1)}-32x^{(5n+3)}\] Now... 4 and 32 are numbers that belong exponentially to 2, am i wrong? \[2x^{2(3x+1)}-2x ^{5(5n+3)}\] Good, with that we can take common factor "2": \[2(x ^{2(3x+1)}-x ^{5(5n+3)})\] That's pretty much as far as we can factor this.
Ok thanks!
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