Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (anonymous):

Two perpendicular chords divide a circle with a radius of 13 cm into four parts. If the perpendicular distances of both chords are 5 cm each from the center of the circle, find the area of the smallest part. I have already found the middle side of the smallest part of the circle which us 5.93. how will i know the other sides of the triangle? Please help me :(

ganeshie8 (ganeshie8):

draw it out first

ganeshie8 (ganeshie8):

|dw:1384338613227:dw|

ganeshie8 (ganeshie8):

something like that u have ?

OpenStudy (anonymous):

yes :)

ganeshie8 (ganeshie8):

|dw:1384338699011:dw|

ganeshie8 (ganeshie8):

|dw:1384338784387:dw|

ganeshie8 (ganeshie8):

lets label things

OpenStudy (anonymous):

hartnn (hartnn):

is there some property that perpendicular from centre to chord, bisects the chord ?

ganeshie8 (ganeshie8):

wow that looks neat :) yes perp from the center bisects the chord..

ganeshie8 (ganeshie8):

looks you have worked most of it already

hartnn (hartnn):

then we have other 2 sides as 7 ....i think...

OpenStudy (anonymous):

am i correct? :)

hartnn (hartnn):

yes, and did you get how its |dw:1384339068869:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!