Two perpendicular chords divide a circle with a radius of 13 cm into four parts. If the perpendicular distances of both chords are 5 cm each from the center of the circle, find the area of the smallest part.
I have already found the middle side of the smallest part of the circle which us 5.93. how will i know the other sides of the triangle? Please help me :(
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ganeshie8 (ganeshie8):
draw it out first
ganeshie8 (ganeshie8):
|dw:1384338613227:dw|
ganeshie8 (ganeshie8):
something like that u have ?
OpenStudy (anonymous):
yes :)
ganeshie8 (ganeshie8):
|dw:1384338699011:dw|
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ganeshie8 (ganeshie8):
|dw:1384338784387:dw|
ganeshie8 (ganeshie8):
lets label things
OpenStudy (anonymous):
hartnn (hartnn):
is there some property that perpendicular from centre to chord, bisects the chord ?
ganeshie8 (ganeshie8):
wow that looks neat :)
yes perp from the center bisects the chord..
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ganeshie8 (ganeshie8):
looks you have worked most of it already
hartnn (hartnn):
then we have other 2 sides as 7 ....i think...
OpenStudy (anonymous):
am i correct? :)
hartnn (hartnn):
yes,
and did you get how its |dw:1384339068869:dw|