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x^2/4,a=4 find the equation of the tangent line
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Linear functions can be written as y=mx+b Your tangent line will have that form. m is f'(a) b is the y-intercept of the tangent line you can use f'(a) along with a point you know is on the line such as (a,f(a)) So you would do this to find b: f(a)=f'(a)*a+b f(a)-f'(a)*a=b So we have b now. Put back into the equation y=f'(a)x+[f(a)-f'(a)*a]
Your first step is to find f'(x)
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