Question

MEDAL FOR BEST ANSWER
how do you put points into standard form?
ex: (1,2) (2,4)

Answer 1

And can you find standard form in just point? ex: (1,2)

Answer 2

Given: (-2,-1) → (2, -6).

x1 = -2
y1 = -1
x2 = 2
y2 = -6

First, determine slope, m:

m = (y2 - y1) / (x2 - x1)
m = [-6 - (-1)] / [2 - (-2)]
m = (-6 + 1) / (2 + 2)
m = -5/4

From the slope-intercept form equation for a line, y = mx + b, we have

y = (-5/4)x + b

Next, calculate b:

b = y / [(-5/4)x]
From one point on the line given (-2, -1), substitute -2 for x and -1 for y:

b = -1 / [(-5/4)(-2)]
b = -1 / (10/4)
b = (-1 / )(10/4)
b = (-1)(4/10)
b = - 4/10
b = -2/5

So, the equation is:

y = (-5/4)x - 2/5, or in decimal form:
¯¯¯¯¯¯¯¯¯¯¯¯¯¯
y = -1.25x - 0.4
¯¯¯¯¯¯¯¯¯¯¯¯¯¯

Answer 3

I have not given the exact solution of ur question..
Replace ur value of x1,x2,y1 and y2