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3/x-2+21/x^2-4=14/x+2 helpppppppppppp meeeeeeeeeeeeee plzzzzzzzzzz
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help me plz
help me plz
\[\frac{ 3 }{ x-2 }+\frac{ 21 }{ x ^{2}-2^{2} }=\frac{ 3(x+2)+21 }{ (x-2)(x+2) }=\frac{ 3x+27 }{ (x-2)(x+2) }=\frac{ 14 }{ x+2 }\]
yes\
is thats it or
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\[3x+27=14(x-2) \] solve for x.
i got 5
than how do i get solution set
u their
Your answer is correct. Gratz! ^^
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but how do i find the solution set
You only got one solution here which is 5. \[solution set= S =\left\{ 5 \right\}\]
k thanks
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