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how do you put y-4=2(x-2) and y-8=2(x-4) into slope-intercept form.
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intercept form is y=mx+b
I know that.. but I have to put those to equations into intercept form... how do I do that?
just simplify the equations
hm, wait..
I think it's y=2x+0 both of them
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y - 4 = 2(x - 2) -- distribute through the parenthesis y - 4 = 2x - 4 -- add 4 to both sides y = 2x + 0 y - 8 = 2(x - 4) -- distribute through the parenthesis y - 8 = 2x - 8 -- add 8 to both sides y = 2x + 0 I agree with lucaz :)
simply solve for y
since it is defined to be y=mx+b all you have to do is solve for y like @texaschic101 did
:)
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