Question

Need help with 2 algebra questions, will give best response if you answer correctly

Answer 1

do you knovv hovv the vvhole subtract vvhen dividing thing vvorks?

Answer 2

i can't do them for you. sorry.

Answer 3

you don't understand how to do them?

Answer 4

i do understand but its going to take a decent amount of time to explain this to you.

Answer 5

can you tell me if my best guesses on them are right or not at least?

Answer 6

i think its either A or B for #4 & it's either C or D for #5.

Answer 7

i can tell you this. for number 4 it is not c and 5 it is not d

Answer 8

hold on give me a minute that is vvrong.

Answer 9

may have given you the ansvvers but dang

Answer 10

im so confused i wish 2 problems didnt have to be so difficult.

Answer 11

you know how when you subtract fractions they have to have the same denominator?
\[\frac{ 1 }{ 2 } + \frac{ 1 }{ 3 } \rightarrow \frac{ 1 }{ 2 }*\frac{ 3 }{ 3 } + \frac{ 1 }{ 3 }*\frac{ 2 }{ 2 } \rightarrow \frac{ 3 }{ 6 } + \frac{ 2 }{ 6 } \rightarrow \frac{ 5 }{ 6 }\] do you understand this?
question 4 is the same idea...

Answer 12

yes I see that

Answer 13

so
\[\frac{ 3x }{ (x+1) } - \frac{ (x-5) }{ (x+6) } \rightarrow \frac{ 3x }{ (x+1) }*\frac{ (x+6) }{ (x+6) } + \frac{ (x-5) }{ (x+6) }*\frac{ (x+1) }{ (x+1) }\]

Answer 14

so #4 would be C?

Answer 15

@jigglypuff314

Answer 16

not quite...
you would simplify the top
3x(x+6) - (x-5)(x+1)
3x^2 + 18x - (x^2 - 4x - 5) then simplify more. what do you get?

Answer 17

if I add 18x and 4x it would be B but if I'm supposed to subtract those it would be A.

Answer 18

I feel like I'm supposed to add them because it's negative so it's B?

Answer 19

3x^2 + 18x - (x^2 - 4x - 5) you distribute the negative
3x^2 + 18x - x^2 + 4x + 5

so B is correct :)

Answer 20

yay! now all I need is the final problem which is 5.

Answer 21

with this one I add 10b and 5b right?

Answer 22

because if so it must be D.

Answer 23

umm, I'm not quite sure what you mean, it was the same idea as the last one so
\[\frac{ 10b }{ (b-2)(3b+1) } + \frac{ (5b+1) }{ (3b + 1) } = \frac{ 10b }{ (b-2)(3b+1) } + \frac{ (5b+1) }{ (3b + 1) }*\frac{ (b-2) }{ (b-2) }\]

Answer 24

you can't add fractions that don't have the same denominator, remember that :)

Answer 25

ohh okay. so it would either be A or B then. I'm going to think .... it's A?

Answer 26

yep :)

Answer 27

yay! thank you so much for being patient with me. you've helped a lot. :) gave you best response btw.

Answer 28

glad I could help :D