what is the x-intercept and y-intercept for this equation: y=-1/2x+3, please help and explain why, thank you
\[y=-1/2x+3\]
to find x int plug in 0 for y to find y int plug in 0 for x
y int is y= -1/3 x int dne
wait there is an x int x = 0 is just a asymptote
This is currently in slope-intercept form. y=mx+b, where m is the slope and b is the y intercept. So first off, your y-intercept would be 3. An x intercept would be where y=0, so we can do that now. 0=-1/2x+3 subtract 3 from both sides. -3=-1/2x Multiply by the reciprocal of -1/2, which is -2/1. 6=x. So the y intercept is (0,3) and the x intercept is (6,0)
okay thank you! that help a lot.
oops, helped
actually, it wouldn't be (6,0) it would be (-6,0)
Yes, it is 6,0. 0=(-1/2)x+3 What multiplied by -1/2 would equal 0? 6. \[-\frac{ 1 }{ 2 }x+3\] \[-\frac{ 1 }{ 2 }(6)+3\] \[0=-3+3\]
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