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Mathematics 17 Online
OpenStudy (anonymous):

|3t+6|<9

jimthompson5910 (jim_thompson5910):

I'll get you started |3t+6|<9 -9 < 3t+6 < 9 and I'll let you take over from here. Tell me what you get.

jimthompson5910 (jim_thompson5910):

by the way, I'm using the rule that if |x| < k then -k < x < k where k is some positive number

OpenStudy (anonymous):

A.-4 B.-1 C.0 D.2 The answer is D but how?

jimthompson5910 (jim_thompson5910):

-9 < 3t+6 < 9 -9-6 < 3t+6-6 < 9-6 ... subtract 6 from all sides -15 < 3t < 3 What's next?

OpenStudy (anonymous):

Divide 3 from all sides

jimthompson5910 (jim_thompson5910):

good, that gives you -15/3 < 3t/3 < 3/3 -5 < t < 1

jimthompson5910 (jim_thompson5910):

Since we know -5 < t < 1, we can say that the variable t is some number between -5 and 1. But t cannot equal -5 and t cannot equal 1

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