Question

x^2+2x-15
solve and explain
its factoring

Answer 1

\[x^2+2x-15\]
So, what we are looking for here is two numbers that add to +2 and multiply to -15.
To make this easier for you, -3 and +5.
So we would make it (x-3)(x+5)
If we multiply it out, we get \[x^2+5x-3x-15\]
Which when we simplify, gives us \[x^2+3x-15\]
Which is what you gave us to begin with. So (x-3)(x+5) is the factored form for that.
As for solve, what do you mean by solve it? Solve it for what exactly?? Do you mean find the zeros?