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derive from equation dy/dx=1+1/2x^2 slope of equation is equale to dy/dx 11/2=1+1/2x^2 9/2=1/2x^2 so x=+-1/3
that's the x coordinate but what about the y?
or is it -1/3, 1/3?
now put x=-+1/3 in the equation and find y you will have two different y
how is that possible if the book says there is just 1x,1y?
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do you get how to do that?
I got (1/3,-7/6) and (-1/3,7/6), is that right?
yes that's right :)
all i did was substitute 1,3 -1,3 back into x-1/2x, which is all it is?
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