Question

Write an equation of a line in slope intercept form that is perpendicular to y = -4x -2 and passes
through the point (-16, -11).

Answer 1

oh boy.

Answer 2

help please :/

Answer 3

The first thing that we need to do is to solve 4x+y+2=0 for y.
In this example we have: y=−4x−2
We can see that the slope of given line is m=−4.
The slope of the perpendicular line is the opposite reciprocal.This means that the perpendicular slope ( m1) can be found by using the formula: m1=−1m. In this case we have:
m1=−1m=−1−4=14
We can conclude that the slope of the line we need to find is m=14. Also, we know that the unknown line is passing through point A = ( −16 , −11 ).
Now we can use the point-slope form to find the line.
The point-slope form is: y−y0=m⋅(x−x0), where m is the slope and (x0,y0) is the given point
In our case:
m=14, x0=−16, y0=−11
After substitution we have:
y−y0y−(−11)yy=m⋅(x−x0)=14⋅(x−(−16))=14⋅x+4−11=14x−7

Answer 4

ah vvhat it didn't post right lame

Answer 5

y = 1/4x - 7

Answer 6

give me one second ill fix up the explanation

Answer 7

imma read all that xD

Answer 8

okay

Answer 9

http://cl.ly/image/1c202Y1S101m

Answer 10

so y = 1/4x - 7 is the answer?

Answer 11

yes sir.

Answer 12

what did you use to solve them .-.

Answer 13

its in the picture i sent o.o

Answer 14

i mean what program haha

Answer 15

did you type all that

Answer 16

yes.

Answer 17

i used a calculator and vvord

Answer 18

http://cl.ly/image/0p2S2r1x2B1q

Answer 19

thanks bro