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Solve for x, if it is a complex number, give answer in terms of i 3x^2=2x^2-2x-1 @jim_thompson5910
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This is my last one. I am completely lost.
@Directrix
3x^2=2x^2-2x-1 3x^2-2x^2+2x+1 = 0 x^2 + 2x + 1 = 0 I'll let you finish
I honestly dont know what to do. Do i solve for x?
If so, it is 1
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yes, but factor first
(X+1)^2=0
good, so x = ???
1?
no
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Let's test it (x+1)^2=0 (1+1)^2=0 .. plug in x = 1 2^2 = 0 4 = 0 ... this is FALSE, so x = 1 is NOT a solution
-1
yep
Check: (x+1)^2=0 (-1+1)^2=0 .. plug in x = -1 (0)^2 = 0 0 = 0 ... this is TRUE, so x = -1 is definitely a solution
Sory, had tha the first time, accidentl forgot the negative
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Now, is this a complex #?
-1 is a real number
So -1 is the. Answer?
yes
Tyvm
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yw
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