Question

MeDaL will be awarded! Help!!
I am given a line, y-10=2/3(x-4)
How do I write a perpendicular to it line, that passes through (4,2) , in a POINT SLOPE form.

Answer 1

I can find a perpendicular slope, is it -3/2?

Answer 2

@undeadknight26

Answer 3

i think point slope form is y = mx + b right?

Answer 4

Idk

Answer 5

I think it is a slope intercept form, isn't it?

Answer 6

I honestly have no idea how to answer this question,,,@texaschic101 i need reinforcements!

Answer 7

@texaschic101

Answer 8

@texaschic101

Answer 9

hehe sorry about disturbing you texas...

Answer 10

point slope form is y - y1 = m(x - x1)
perpendicular line will have negative reciprocal of the given slope, therefore, the slope you need is -3/2
(4,2) x1 = 4 and y1 = 2
now we sub...
y - y1 = m(x - x1)
y - 2 = -3/2(x - 4) <-- point slope form

Answer 11

That's it, this is the answer?

Answer 12

yes...if they want it in point slope form...now if they want it in slope intercept form, we would have to solve for y. The answer in point slope form is : y - 2 = -3/2(x - 4)

Answer 13

Ty! I gave you 6-7 medals, right? Id care about medals, I just need help.
Ty for helping me!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 14

no problem...glad to help :)