Gravity on the Moon is much weaker than on Earth. The expression below can be used to approximate the time in seconds it takes for an object to reach the surface of the Moon, when dropped from a height of h meters. To the nearest hundredth of a second, how long would it take for an object dropped from a height of 50 meters to land on the Moon? (Enter only the number, such as 3.25 without units.) √h/0.82
I don't understand... can someone explain please?
well how long does it take for a object on earth to fall 50 meters? does it say that at all?
is that what the 0.82 is then?
you would take the time it would take to fall 50 meters on earth and then multiply that time by .82 and you would get how long it would take to fall 50 meters on the moon.
41?
do you know how long it would take something to fall 50 meters on earth?
no, I didnt see that in the q...
hmmm. thats odd. i dont see how you could find the time of it on the moon if you didnt know the time on earth? did you learn it in your lesson by any chance?
no, this is an idependant project that is to prove we learned the concept
i dont know what to tell you. sorry. that seems like a really dumb question.
i mean like whoever made the question needs to think it through more. not you :P
Use the expression given. plug 50 in for h \[\sqrt{50/.82}\]
that equals about 7.81
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