4y + 3 <= y + 6?
solve as you would have had it simply been an = instead of <= so subtract a y from both sides then subtract a 3 from both sides then divide both sides by 3
Hey wolf man whats up wit da pic?!
Why did you copy my picture. >:(
lol don't do that wolf man...I know i had this picture b4 you lol...
I was just kidding bro, chill...
\(\huge {4y+3≤ y + 6}\) \(\huge {subtract}\) \(\huge {3}\) \(\huge {from}\) \(\huge {both }\) \(\huge {sides}\) \(\huge {4y+3-3≤ y + 6-3}\) \(\huge {4y≤ y + 3}\) \(\huge {subtract}\) \(\huge {y}\) \(\huge {from}\) \(\huge {both }\) \(\huge {sides}\) \(\huge {4y-y≤ y + 3-y}\) \(\huge 3y≤ 3}\) \(\huge {divide}\) \(\huge {both}\) \(\huge {sides }\) \(\huge {by}\) \(\huge {3}\) \(\huge {y≤ 1}\)
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Ty, how about -2y>2
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