Question

d/dx [ln(x^3 + 1) + e^4x]
How do I start this?

Answer 1

I'll give material that you'll need to DIY:
\[\frac{ d \ln (A) }{ dx } = \frac{ \frac{ d A }{ dx } }{ A }\] \[\frac{ d e ^{A} }{ dx }=\frac{ d A }{ dx }*e ^{A}\]

Answer 2

I don't understand how it is applied

Answer 3

\[\frac{ d \ln(x ^{3}+1) }{ dx }=\frac{ \frac{ d (x ^{3}+1) }{ dx } }{ x ^{3}+1 }=\frac{ 3x ^{2} }{ x ^{3}+1 }\] You do the same for d/dx(e^4x) and then you sum the results.