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Firejay5 Write a polynomial function of least degree with integral coefficient that has the given zeros. 2i, 3i, and 1
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You have 3 equations\[(x-2i), (x-3i), (x-1)\]If you multiply them, you get a 3rd degree polynomial where the zero's are at 2i, 3i, and 1.
How would I put in to an equation
I got (x^2+5ix-6),(x-1). Is that right?
You'll also have to multiply those two to get one function.
Thanks
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