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1+tan^2x/csc^2x=tan^2x Please help !
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@Hero ???
Step 1: change 1 + tan^2(x) into sec^2(x) it is a Pythagorean identity.
Thats how far i got.
Step 2: Change the right side: tan^2(x) = sin^2(x)/cos^2(x) Are you with me?
yes :)
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On the left side, change sec^2(x) into 1/cos^2(x) and change csc^2(x) into 1/sin^2(x)
so the left side is just 1/cos^2(x) divided by 1/sin^2(x) which is just sin^2(x)/cos^2(x) which is equal to the right side which is sin^2(x)/cos^2(x). Done.
@zaragoza96 Do you understand every step?
so why is it flipped, what is canceled out in order to have sin on top ?
When you divide, you flip
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watch.........
That was very helpful, Thank you so much !
|dw:1384483266031:dw|
See what I did?
yes , you are the best !
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Very welcome.
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