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How do you integrate sin (x^2)?
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\[\int\sin(x^2)\,\mathrm dx\]
let \(u=x^2\) \(u^{1/2}=x\) \(\tfrac12u^{-1/2}\,\mathrm du=\mathrm dx\)
hmm, it doesn't really seam to work out nice, are you sure your question wasn't ∫sin^2(x) dx ?
Yes, I'm sure- that's how the question was framed. Maybe it was a mistake from the examiner's end?
\[=\frac12\int u^{-1/2}\sin(u)\,\mathrm du\]
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@sauravshakya
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