Given 2x – 3y = 6 find the missing value in each ordered pair. (0, ), ( ,0), (6, ), ( , -4 )

Question

Given 2x – 3y = 6 find the missing value in each  ordered pair.   (0,   ),  (   ,0),   (6,   ),  (   , -4 )

kainui · Answer

Ahh, show me your best guess and we'll go from there. Remember that in an ordered pair the first number is the x-coordinate and the second one is the y-coordinate. Since they're linked by an equation, if you know one, you already have a way to find the other.

anonymous · Answer

I honesty have no idea what to do. I thought about putting the 0 in for the xand making it 2(0)-3y=6 but i dont know what to do after that

tkhunny · Answer

Obviously, you DO have an idea.  The substitution was fine.  Now, solve for y.  What else would you do?

anonymous · Answer

thats where im stuck

tkhunny · Answer

Okay, solve this for w

2w = 4

anonymous · Answer

you would divide 2w by 2 and 4 by to so w=2

tkhunny · Answer

Okay, solve this for s.

s - 4 = 3

anonymous · Answer

add 4 to the -4 and add 4 to the 3.  s=7

tkhunny · Answer

There you go.  You have all the skills you need to solve this expression for y.

2(0)-3y=6

Go!

anonymous · Answer

well i think the 0 goes away because it doesn't make a difference when your subtracting... 3y=6 so i just divide 3y by 3 and 6 by 3 so y=2

tkhunny · Answer

So close!!

2(0) - 3y = 6

0 - 3y = 6

-3y = 6

y = -2

You just lost  a sign in there.

Sweet!  Do the next value.

anonymous · Answer

so i think it would make it 2x-3(0)=6
                                      2x-0=6
                                      2x=6
   then 2x/2 amd 6/2
x=3

tkhunny · Answer

Yes!