Find the coordinates of the vertex for the parabola defined by the given quadratic function:
f(x)=x^2+2x-8

Question

Find the coordinates of the vertex for the parabola defined by the given quadratic function:
f(x)=x^2+2x-8

anonymous · Answer

Given function is a parabola of the standard form: -A(x-h)^2+k, with (h,k) being the (x,y) coordinates of the vertex. A is a multiplier which affects the steepness or slope of the parabola. The minus sign of the lead coefficient means that the parabola opens downwards, that is, it has a maximum.
..
Finding the coordinates of the vertex:
f(x) = -x^2 -4x + 8

 
completing the square
y=-(x^2+4x+4)+8+4
y=-(x+2)^2+12
Ans:
Coordinates of the vertex: (-2,12)

grant330sims · Answer

well, i know thats not right, I know the x is -1, because of -b/2a. But after that, dont you just put the x in to find y?